divers helmet distributor

K

khnaess

Member
Hello
I am trying to understand the modification that the previous owner of my 1937 V8-60 have done to the ignition system but I need a little help. I understand that this system operate on 4V, but my resistor under the dash seems to be bypassed by a wire , and I have a seperate after marked Bosch coil wich I suspect is 6V. So what do we see on the top of the distributor on the attached Picture? The LT wire from the coil goes first to the longest "cylinder" of the top of the distributor. Then there is a a orange wire that takes it to the next "cylinder" that is a little smaller. Wich one is the resistor and wich one is the condenser?
Can anyone explain to me how the current flows from the coil to the breaker point in my system? I cannot see where the wire goes into the distributor, its a narrow place down there
Thanks
Knut Haakon
 

Attachments

  • IMG_0452.jpg
    IMG_0452.jpg
    47.5 KB · Views: 112
JSeery is correct, I think. 2 condensors. Maybe one is for radio suppression.
In any event, on top of the dist is a conversion piece to be able to use a separate coil, which you have. The resistor would be located on the inside of the cab on the firewall, somewhere around the middle, I think

BTW, does it run?
 
Last edited:
The coil may have an internal resistor, if that is the case you would not need the one under the dash. Modern coils, which I believe the Bosch is, typically have them built in. I run a new aftermarket coil on my crab distributor and don't use a resistor.
 
Thank you for answers!
The car runs fine but I just try to understand the system. Sooner or later it will need repair.
The coil is a Bosch blue coil and I guess it has an internal resistor. The label on the coil is worn so I cannot read the spec. But I measured the resistance to be 1,5 ohm so suppose its ok. (The car has also been going like this for several years without burning points)
But I dont know why there is 2 condensers? Strange....
 
Another question from the beginner:
I tried to measure the output voltage of the coil to see if it was about 4 V but I didnt manage.
The wire from the ignition goes to the (-) side of the coil and this side shows 6V on the volt meter. But the (+) pole that goes to the distributor didnt have any current at all. In my mind it should have about 4 volt due to the internal resistor. Is this because the points are in an open position? Would it be possible to measure if I crank the engine a little bit?
regards
Knut H
 
khnaess said:
Another question from the beginner:
I tried to measure the output voltage of the coil to see if it was about 4 V but I didnt manage.
The wire from the ignition goes to the (-) side of the coil and this side shows 6V on the volt meter. But the (+) pole that goes to the distributor didnt have any current at all. In my mind it should have about 4 volt due to the internal resistor. Is this because the points are in an open position? Would it be possible to measure if I crank the engine a little bit?
regards
Knut H
Click to expand...

You are unable to measure the voltage because the points are closed making that wire the same as ground. Open the points the you will be able to read the voltage.
 
On how the wire reaches the points...the plastic plate on top where your non-stock coil attaches is made like the bottom plate of the original coil. The primary current to points is carried by a spiral coil spring on the bottom of the plate pressing against a connection directly to the points inside.
 
You must log in or register to reply here.
Back
Top