I know Rockfla said ONE more time, but it's been bugging me. I understand the concept of bypassing the resistor wire or ballast with a jumper. But how is voltage maintained at the coil? The battery voltage is going to be drawn down with the load when the starter is engaged. A diode isn't going to maintain it at 6volts.
Lets say your battery reads 6.4 volts no load.Hit the starter button, starter engages. The battery is going to read say for argument sake 5.9 volts. The coil is going to see 5.9 volts.
A DuckDuckGo search, I don't use goggle anymore, did not show any results.