Brent, The torque at the end of a lever does not vary depending upon whether it has gone over center or not. [FONT="]M[/FONT][FONT="] = Fd[/FONT][FONT="], where F is the force at the end of the lever, d is the distance between the force and the fulcrum, or the length of the lever, and M is the turning force known as the moment or torque.[/FONT] The torque is purely a function of the length of the lever and the force being applied to the other end. It is true, though, that for a lever moving in a 90 degree arc from vertical to horizontal, that there are both vertical and horizontal components to the circular movement at the end of the lever. The closer you are to vertical, the horizontal component of the distance traveled is greater for every degree of circular movement, and that horizontal component decreases the further you move away from vertical. Translated to Model A terms, as the brake cross shaft lever just starts to move away from vertical, it pulls the brake rod the greatest horizontal distance, and the horizontal distance it can move the rod decreases as the angle of the cross shaft lever increases. But the force at the end of the lever remains constant. So perhaps, if you have a really sloppy brake system where the bushings are worn out and the clevis pins are loose, you will need a greater horizontal pull on the brake rods to take up the slack before the force at the end of the lever is transmitted to the brake shoes. Starting the brake cross shaft lever a few degrees on the other side of vertical so that it goes over vertical as it pulls will give you the greatest length of pull to take up that slack. But if your bushings and clevis pins are tight and there is no lost motion, there will be the same braking force at the end of the lever whether is starts from or ends at a vertical position.