drive line gurus

fordor41

fordor41

Well-known member
Our '60 was lowered by p.o. about 4". Today I checked the U-joint angles with a laser and found that a straight line from the trans was about 2" lower than the pinion by 2 deg. The pinion angle was dead on the trans output shaft. So I figured if I put 2 deg. shim in the rear to aim the pinion up 2 deg the angles would be equal. But now the angles would be reversed from usual, instead of trans to drive shaft down and drive shaft to pinion up it would be trans to D.S. up and D.S. to pinion down. the angles would be equal but reversed. anyone see a problem?
 
I am trying to not get confused as to what we are discussing here, either u-joint angles OR trying to make the trans output shaft parallel with the pinion shaft. So when your trans shaft and pinion shaft are parallel your u joint angles will match automatically. This does not say that your u joint angles are within a reasonable operating angle but only that both joints are at the same angle. So are your trans shaft and pinion shaft parallel?
 
I believe that’s what he wants to accomplish with the shims, and confused the question with all those extra words! 😏
 
yes, I'm trying to get the trans center line parallel to pinion center line but the drive shaft will actually go upwards from the trans as opposed to usual downward angle from trans. I "assume" both set-ups will operate the same
 
Check out the link I posted earlier and watch the video on that location. Changing directions between the trans and driveshaft increases the operating angle of the joint. Calculate the operating angles for both joints to verify they are not excessive.
 
fordor41 said:
yes, I'm trying to get the trans center line parallel to pinion center line but the drive shaft will actually go upwards from the trans as opposed to usual downward angle from trans. I "assume" both set-ups will operate the same
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Yes, they will. Your driveshaft will not care if it goes uphill or downhill. As long as the trans is parallel to he pinion.
 
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