I hate to do this to you, but let's take one more crack at this from the theoretical end of things. The first thing you should know is that the points that we use can handle up to about 4 amps of current before they start to pit and deteriorate rapidly. Since Ohm's Law says that current=voltage divided by resistance, we can determine the resistance of the coil by application of this formula, since we know two of the factors. 12 volts/3 ohms = 4 Amps. In the same vein, 6 volts/1.5 ohms = 4 amps. Thus, in any ignition circuit, you want 4 amps total current through the coil system. 6 volt systems were designed with 1.5 ohm coils from the start. With a twelve volt system, some genius knew that you would get a hotter spark by running a full 8 amps through the system. This is done by using a 1.5 ohm coil in a 12 volt system, using a ballast resistor to add another 1.5 ohms to the circuit during normal running. Bypassing this resistor makes more power for the ignition system while starting. This is usually done by bypassing the ballast resistor from the starter solenoid. Thus, a six volt system will always have a 1.5 ohm coil, while a 12 volt system could have either a 1.5 or 3 ohm coil, depending on whether it has a ballast resistor or not. A multi-meter is invaluable of determining the internal resistance of a coil.
Pre '48 Fords are different, in that they have a variable resistor, not a ballast resistor. This type of resistor will have zero resistance when cold, allowing a full 6 volts to go to the coil on initial startup, but will then heat up when used. which will increase crease the resistance, therefore reducing the voltage to the coil (and therefore the current in amps) across the points.
I have to say that I have little knowledge of the "ever popular" Skip's Coils so have no knowledge of how they work within the system.