1936 Ford Tudor original drive train

A

alrivera

Member
City
Denver City
State
Texas
Price
$400
I have removed the complete original front end and the complete original rear end from my 36 Ford Tudor Sedan. Drive train rolled around good and was not locked down. Have factory wheels, brakes, wishbones, springs, crossbraces, etc. Will take $400 for the front half, $400 for the back half. I believe this is a reasonable price for these parts. I just do not need them anymore. Have brake and clutch pedals, battery box bracket, center crossbrace plates, make offer on any of this. Thanks, Al :cool:
 
Wamnram, I do not know what ratio the rear end is. How can I tell, and also where is the speedo drive gear located? I will be glad to check if you will give me some information. Thx, Al
 
You can check the differential to see if there is a metal tag with some numbers or the ratio stamped on it that is held on by one of the axle housing bolts, or, while someone is holding one of the wheels or hubs from spinning, turn the other wheel one revolution and count the number of revolutions of the drive shaft. For one complete turn of the wheel, the drive shaft should turn something like 4.11 or 3.78 times. It is sometimes hard to tell the difference between the ratios in one turn of the wheel, so you could turn the wheel ten times and count the number of revolutions of the drive shaft and then divide by ten. The speedometer gear is a little 'turtle looking cap held on to the drive shaft housing by two 1/4" bolts near the end where the drive shaft ptotrudes from the housing. It will usually (but not always) have a number on it like 18, 19, 20 or 21.
 
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